Let AM be the distance between point A and the right wall and AN be the distance between A and the left wall.
Δ AMB is an isosceles right triangle and Δ ANC is half of an equilateral triangle.
Length of AM = 30 m. Length of AN = 1/2 · 80 = 40 m.
The distance between the walls is:
30 m + 40 m = 70 m.
Answer:
A
Step-by-step explanation:
if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0
reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0
center is (2,-4)
r=√(2²+(-4)²-(-14))
=√(4+16+14)
=√(34)
eq. of circle is (x-2)²+(y+4)²=34
or
(x²-4x)+(y²+8y)=14
(x²-4x+4)+(y²+8y+16)=14+4+16
(x-2)²+(y+4)²=34
f(-10) = 4
f(-2) = 4
Since y is constant while x isnt we just dont need to put x
f(x) = 4
Answer:
1 true good statement can prove his friend wrong.
Step-by-step explanation:
Answer is 1.
Answer:
C. 364.4
E. 14
F. 21
G. 96°