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Kryger [21]
3 years ago
5

Tell whether it is possible to draw a triangle with the given side lengths.

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

Since the 2 shorter sides are greater than the longest side when added, it meet the triangle inequality thoerem. Triangle Inequality Theorom: The longest side of a triangle is less then the 2 shorter sides added.

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Please help me ................
Angelina_Jolie [31]

Answer: AAS

Step-by-step explanation:

8 0
3 years ago
What is equivalent to 5^3•5^4
mafiozo [28]

Answer:

{5}^{7}

Step-by-step explanation:

5^3•5^4 =  {5}^{3 + 4}  =  \purple{ \bold{ {5}^{7} }}

8 0
3 years ago
Write a related subtraction fact for 9+3=12. Explain how the two facts are related
postnew [5]
12-3=9 they switch up and it still equals the same thing
5 0
3 years ago
Read 2 more answers
A segment in the complex plane has a midpoint at –1 + i. If the segment has an endpoint at –5 – 7i, what is the other endpoint?
morpeh [17]

Answer:

The other end point is: s+ti = 3+9i

Step-by-step explanation:

Mid-Point(M) in the complex plane states that the midpoint of the line segment joining two complex numbers a+bi and s+ti is the  average of the numbers at the endpoints.

It is given by:    M = \frac{a+s}{2} +(\frac{b+t}{2})i

Given: The midpoint = -1 + i and the segment has an endpoint at -5 - 7i

Find the other endpoints.

Let a + bi = -5 -7i  and let other endpoint s + ti (i represents imaginary )

Here, a = -5 and b = -7 to find s and t.

then;

-1+i = \frac{-5+s}{2} + ( \frac{-7+t}{2})i     [Apply Mid-point formula]

On comparing both sides

we get;

-1 = \frac{-5+s}{2}  and  1 = \frac{-7+t}{2}

To solve for s:

-1 = \frac{-5+s}{2}

or

-2 = -5+s

Add 5 to both side we have;

-2+5 = -5+s+5

Simplify:

3 = s or

s =3

Now, to solve for t;

1 = \frac{-7+t}{2}

2 =-7+t

Add 7 to both sides we get;

2+7 = -7+t+7

Simplify:

9 = t

or

t =9

Therefore, the other end point (s+ti) is, 3+9i




4 0
3 years ago
Read 2 more answers
Please help!!!<br><br> i need help with this
goblinko [34]

Answer:

Step-by-step explanation:

Combine like terms. Like terms have same variable with same power

a) (2xy + 4x) + (15xy - 5x)  = <u>2xy + 15xy</u> +<u> 4x - 5x</u>

                                         = 17xy - x

b) (6a + 4b² - 3) + (3b² - 5) = 6a + <u>4b² + 3b²</u>  <u>- 3 - 5 </u>

                                           = 6a + 7b² - 8

c) (4x³ - 3x² +4x) + (8x² - 5x ) = 4x³ <u>- 3x² + 8x²</u>  <u>+ 4x - 5x</u>

                                               = 4x³  + 5x² - x

d) (7b - 6a  + 9y) - (12b + 5a - 2y) =

In subtraction, add the additive inverse of (12b + 5a - 2y)

additive inverse = - 12b  - 5a  + 2y

(7b - 6a  + 9y) - (12b + 5a - 2y) = 7b - 6a + 9y  -12b -5a + 2y

                                                   = 7b - 12b  -6a - 5a  + 9y + 2y

                                                   = -5b - 11a + 11y

e) (2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)

Additive inverse of  13x + 4x² + 5 - 6y = -13x + 4x² - 5 + 6y

(2x² + 7x - 2 + 9y) - (13x + 4x² + 5 - 6y)= 2x² + 7x - 2 + 9y -13x - 4x² -5 +6y

                    = 2x² - 4x² + 7x -13x -2 - 5 + 9y + 6y

                    = -2x²  - 6x  - 7 + 15y

5 0
2 years ago
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