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2 years ago

Find both solutions for the variable b^2+ 9b+ 18=0

1 answer:

7 0

If you would like to solve the equation b^2 + 9 * b + 18 = 0 for the variable b, you can do this using the following step:

b^2 + 9 * b + 18 = 0
(b + 3) * (b + 6) = 0

Result:
1. solution: b = - 3
2. solution: b = - 6

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Step-by-step explanation:

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Write an equation in slope-intercept form for the line with slope 8 and y-intercept -9

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Y=8x-9

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The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e

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Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

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So, for that we will apply the following sequence of translations:

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2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

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3 years ago

If you wanted to find the mean height of students in an elementary school,

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3 years ago

21. Paul has $900 to invest in a savings account that has an annual interest rate of 1.8%, and a money market account that pays

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The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

The interest earned after one year is 0.018·x

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing x dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

$\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}$

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

$\displaystyle Interest, \ I = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}$

Plugging in the values gives;

$\displaystyle I = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x$

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

$\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}$

Which gives;

$\displaystyle Interest = \frac{x \times 1.8 \times 1}{100} = 0.018 \cdot x$

Interest earned by investing in the savings account for one year, I = 0.018·x

The polynomial representing the interest earned is I = 0.018·x

Learn more here:

brainly.com/question/11314161

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2 years ago