4/5x + 7= 10 what's the value of x?

Need math help As soon as possible

ehidna [41]

i believe the answer is B

but i could always be wrong :(

8 0

3 years ago

Read 2 more answers

Write eight ten thousands, five hundreds, two tens, seven ones

Alecsey [184]

THE ANSWER IS 80,527

6 0

3 years ago

11) What is the y-intercept of the function?

irina1246 [14]

The answer would be (-5,0)

5 0

3 years ago

A librarian is expanding some sections of the city library. He buys book at a special price from a dealer who charges one price

stiks02 [169]

Answer:

The special price of 1 hardcover book = $13

The special price of 1 paperback book = $6

Step-by-step explanation:

Here, let us assume the special price of 1 hardcover book = $ m

and the the special price of 1 paperback book = $ n

Now, the price of 12 hardcover books = 12 x ( Price of 1 hardcover) = 12 m

and the price of 73 paperback books = 73 x ( Price of 1 paperback) = 73 n

Also, The price paid for 12 hardcover and 73 paperback books is $594

⇒ 12 m + 73 n = 594 ....... (1)

Similarly:

The price of 11 hardcover books = 11 x ( Price of 1 hardcover) = 11 m

The price of 87 paperback books = 87 x ( Price of 1 paperback) = 87 n

Also, The price paid for 11 hardcover and 87 paperback books is $665.

⇒ 11 m + 87 n = 665 ....... (2)

Now, solving both equation for the value of m and n , we get:

12 m + 73 n = 594 x 11

11 m + 87 n = 665 x (-12)

we get: 132 m + 803 n = 6534

- 132 m - 1044 n = - 7980

adding both equation, we get:

132 m + 803 n - 132 m - 1044 n = - 7980 + 6534

or, - 241 n = - 1446

or, n = 1446/241 = 6, or n = 6

Now, Substituting n = 6 in 12 m + 73 n = 594 ,

we get: 12 m + 73 ( 6) = 594, m = 13

Hence, The special price of 1 hardcover book = $13

and The special price of 1 paperback book = $6

7 0

3 years ago

A 15-ft ladder rests against a vertical wall. If the top of the ladder slides down the wall at a rate of 0.33 ft/sec, how fast,

3241004551 [841]

Answer:

0.44 ft/sec.

Step-by-step explanation:

Let A is the bottom of the ladder and AB is the distance from the bottom of the wall i.e. B is the bottom of the wall. If C is the top of the ladder and BC is the height of the wall.

Now, Δ ABC is a right triangle and AC is the length of the ladder i.e. hypotenuse.

Now, AC² = AB² + BC² {From Pythagoras Theorem}

Now, differentiating both sides with respect to time t, we get

$0 = 2 \times (AB) \times \frac{d(AB)}{dt} + 2 \times (BC) \times \frac{d(BC)}{dt}$

⇒ $\frac{d(AB)}{dt} = - \frac{BC}{AB} \times \frac{d(BC)}{dt}$

Now, given that $\frac{d(BC)}{dt} = - 0.33$ feet/sec.

Hence, $\frac{d(AB)}{dt} = - \frac{BC}{AB} \times (- 0.33)$ ......... (1)

Now, given that AB = 9 ft. and AC = 15 ft.

So, 15² = 9² + BC²

⇒ BC² = 144

⇒ BC = 12 feet.

Now, from equation (1), we get

$\frac{d(AB)}{dt} = - \frac{12}{9} \times (- 0.33) = 0.44$

Therefore, the bottom of the ladder is sliding away from the wall at the rate of 0.44 ft/sec. (Answer)

3 0

3 years ago

4/5x + 7= 10 what's the value of x?​

4/5x + 7= 10 what's the value of x?