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irina [24]
3 years ago
9

Check out the attachment and help me out please!!!

Mathematics
1 answer:
Aleks [24]3 years ago
5 0

Answer:

20

Step-by-step explanation:

4 + 2 + 5 + 4 + 0 + 1 + 1 + 3 = 20

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Can someone help? Thanks :D
Rufina [12.5K]

Answer:

y\leq -x+4

Step-by-step explanation:

The first thing that we can do is look at the equation of the line and then worry about the inequality afterwards.

This line has a y-intercept of 4 and a slope of -1.

This means that the equation of this line would be y=-x+4

Now that we have the equation of the line, we just need to determine which inequality sign to use.

As the shaded region is BELOW the line, we will use a less than (<) sign.

As the line is fully shaded, I can only assume that it is meant to include the line, which would mean that y\leq -x+4 would be the equation for this inequality.

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3 years ago
Calculus question plzzzz
miss Akunina [59]

Answer:

Step-by-step explanation:

f(x)=\frac{1}{\sqrt{x} }\\f'(x)=-\frac{1}{2} x^{-\frac{3}{2}}\\\\f'(4)=-\frac{1}{2} 4^{-\frac{3}{2} }=-\frac{1}{2} \frac{1}{4^\frac{3}{2} } \\=-\frac{1}{2} *\frac{1}{8}=-\frac{1}{16}  \\when x=4\\y=f(x)=\frac{1}{\sqrt{4} } =\frac{1}{2} \\\\eq.~ of ~tangent ~line~is\\y=-\frac{1}{2} -\frac{1}{16} (x-4)

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3 years ago
What’s the correct answer
labwork [276]

There's a strong negative association between the two variables.


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Read 2 more answers
The sector COB is cut from the circle with center O. The ratio of the area of the sector removed from the whole circle to the ar
mafiozo [28]

Answer:

Ratio = \frac{R^2 - r^2 }{ r^2}

Step-by-step explanation:

Given

See attachment for circles

Required

Ratio of the outer sector to inner sector

The area of a sector is:

Area = \frac{\theta}{360}\pi r^2

For the inner circle

r \to radius

The sector of the inner circle has the following area

A_1 = \frac{\theta}{360}\pi r^2

For the whole circle

R \to Radius

The sector of the outer sector has the following area

A_2 = \frac{\theta}{360}\pi (R^2 - r^2)

So, the ratio of the outer sector to the inner sector is:

Ratio = A_2 : A_1

Ratio = \frac{\theta}{360}\pi (R^2 - r^2) : \frac{\theta}{360}\pi r^2

Cancel out common factor

Ratio = R^2 - r^2 : r^2

Express as fraction

Ratio = \frac{R^2 - r^2 }{ r^2}

6 0
2 years ago
Solve for missing angle.Justify and explain your calculations
myrzilka [38]
The missing angle would be 68 because the the triangles can be alternate exterior
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