The absolute value is defined as
So for example, if <em>x</em> = 3, then |<em>x</em>| = |3| = 3, since 3 is positive. On the other hand, if <em>x</em> = -5, then |<em>x</em>| = |-5| = -(-5) = 5, since -5 is negative. The absolute value is always positive.
For the inequality |7 + 8<em>x</em>| > 5, you consider the two cases where the argument to the absolute value (the expression you find inside the bars) is either positive or negative.
• If 7 + 8<em>x</em> ≥ 0, then |7 + 8<em>x</em>| = 7 + 8<em>x</em>, so that
• Otherwise, if 7 + 8<em>x</em> < 0, then |7 + 8<em>x</em>| = -(7 + 8<em>x</em>), so that
The solution to the inequality is the union of these two intervals.
The answer is A
the answer is A
700
what i did was i divided 7000 by 10 and i got 700. then to check, i multiplied 700 by 10 and got 7000
No, (2 , 3) does not satisfy the inequality 4x + 3y > 20.
See attached picture:
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Answer:
local calls per 1 long distance call.
Step-by-step explanation:
Local calls 
Long distance calls 
For 20 long distance calls local call ![=35 For 1 long distance calls local call [tex]=\frac{35}{20} =\frac{7}{4}](https://tex.z-dn.net/?f=%3D35%20%3C%2Fp%3E%3Cp%3EFor%201%20long%20distance%20calls%20local%20call%20%5Btex%5D%3D%5Cfrac%7B35%7D%7B20%7D%20%3D%5Cfrac%7B7%7D%7B4%7D)
Answer:
137 + x <= 170
Step-by-step explanation:
The following inequality will describe this scenario.
137 + x <= 170
the variable x in this scenario represents the total number of cars that you will purchase. This number is added to the number of toy cars that you already own which is 137. As long as this sum is less than or equal to 170 then your storage case will hold them.
