Given:
52 weeks in a year
Hana's age: 11 years
Find her age in weeks.
f(x) = 52x ; where x is the number of years.
f(11) = 52(11)
f(11) = 572 weeks
Hana is 572 weeks old.
Answer:
7^5
Step-by-step explanation:
7x7x7x7x7 is equal to 7^5. Depending on how much sevens there are, that is the power number. In this case there are 5 sevens so that means it is 7^5.
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The answer is b 5x-y=7 2x+y=0
Starting off, we can multiply the third equation by 2 and add it to the third to get rid of both the x and y variables. Next, we get z=1. Plugging that into 3y-5z=-23, we get 3y-5=-23. Adding 5 to both sides, we get 3y=-18. After that, we can divide both sides by 3 to get y=-6. Plugging that into -2x-y-z=-3, we get -2x+6-1=-3=-2x+5. Subtracting 5x from both sides, we get -2x=-8. After that, we can divide both sides by -2 to get x=4.
Groups of four for the group of 288 and groups of five for the group of 360