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Butoxors [25]
3 years ago
7

Find midpoint of (5,2),(-4,-3)

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

The midpoint would be (1/2,-1/2)

Step-by-step explanation:

You might be interested in
A student answered 86 problems on a test correctly and received a grade of 98%. How many problems were on the test, if all the p
balu736 [363]

Answer:

88 problems

Step-by-step explanation:

Set this problem up as fractions

86/x = 98/100

Cross multiply

86 × 100 = x × 98

8600 = 98x

Divide both sides by 98

87.75... = x

Round to nearest whole number

87.75 rounds up to 88

88 problems

7 0
3 years ago
What is the period function of f(x)=1/2tan (2x+5)
soldi70 [24.7K]

Compare your f(x)=1/2tan (2x+5) to

g(x)=a*tan (bx + c).


Note how b = 2.


The period of the given tangent function is pi/b, which here is pi/2, or 90 degrees. Multiplying x by 2 horizontallyl compresses the graph of tan x by a factor of 1/2.

6 0
3 years ago
Subtract: 2x2 - 4x - 3 from x2 - 5x - 8.
VladimirAG [237]
X^2 - 5x - 8 - <span>2x^2 + 4x + 3
= -x^2 - x - 5 

hope that helps</span>
7 0
3 years ago
Read 2 more answers
3 is 12% of please help asap
Korvikt [17]

Answer:

25%

Step-by-step explanation:

hopes this helps you

8 0
3 years ago
Read 2 more answers
Find the distance between each pair of points E(-1, 0),F(12, 0)
Olegator [25]

Answer:

The answer is

<h2>13 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

E(-1, 0) and F(12, 0)

The distance between them is

<h3>|EF|  =  \sqrt{ ({ - 1 - 12})^{2}  +  ({0 - 0})^{2} }  \\  =  \sqrt{ ({ - 13})^{2} }  \\  =  \sqrt{169}</h3>

We have the final answer as

<h3>|EF| = 13 \:  \: units</h3>

Hope this helps you

5 0
3 years ago
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