Answer:
22.5 yards
Step-by-step explanation:
10 costumes at 2.25 yards each is ...
10 · 2.25 = 22.5 . . . . yards of material
Answer:
the answer is that he would have to win 7 games in a row to get 75%
Step-by-step explanation:
Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2
This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that
g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2
So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).
Here's proof of both claims
-----------------------------------------
Proof of Claim 1:
f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6
-----------------------------------------
Proof of Claim 2:
h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2
Answer:
l think it is 117days
Step-by-step explanation:
80%of365
80/100 of 365=116.8
l rounded the answer n got 117days
if you find this helpful plz follow me
n plz Mark my answer
have a nice day
The number of microorganisms that I will have after 10 days would be: 245.41 microoganisms.
<h3>How to calculate the number of microorganisms that I will have after 10 days?</h3>
To calculate the number of microorganisms that I will have after 10 days, I must perform the following operations:
We need to find 37% of 55 as shown below:
- 55 ÷ 100 = 0.55
- 0.55 x 37% = 20.35
- 55 + 20.35 = 75.35
So after 2 days I will have 75.35 microorganisms.
- 75.35 ÷ 100 = 0.75
- 0.7535 x 37% = 27.87
- 75.35 + 27.87 = 103.22
On the fourth day I will have: 103.22 microorganisms.
- 103.22 ÷ 100 = 1.0322
- 1.0322 x 37% = 38.19
- 103.22 + 38.19 = 141.41
On the sixth day I will have 141.41 microorganisms.
- 141.41 ÷ 100 = 1.4141
- 1.4141 x 37% = 52.32
- 141.41 + 52.32 = 193,73
On the eighth day I will have 193.73 microorganisms.
- 193.73 ÷ 100 = 1.9373
- 1.9373 x 37% = 71.68
- 193.73 + 71.68 = 265.41
On the tenth day I will have 245.41 microoganisms.
Learn more about percentages in: brainly.com/question/13450942
#SPJ1
