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2 years ago

7

Evaluate the integral (tan3x)dx

1 answer:

Ksju [112]2 years ago

5 0

<span>The solution to the problem is as follows:

tan (3x) = sin(3x) / cos(3x)

let u = cos(3x), du = -3 sin(3x)

Integrating -1/3 du / u = -1/3 ln (u) = -1/3 ln (abs (cos(3x)) + constant

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<h3>How to determine the difference?</h3>

The expression is given as:

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