What is the simplified form of the following expression? 4t^-5 ∙ 2t^-3

Three fences on a ranch measure 15/16 miles 7/8 miles and 7/16 miles which is the best estimate of the total length of all three

gizmo_the_mogwai [7]

2.25.....
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6 0

3 years ago

Three numbers multiplied together give an answer of -12. The sum of two of the numbers is zero. What could the three numbers be?

Angelina_Jolie [31]

-2,2,3 since 2*-2*4 = 12 and -2+2=0

3 0

3 years ago

18 = 3(3x – 6) Step by step

butalik [34]

Start by multiplying 3 times 3x to get 9x. Then multiply 3 times -6 to get -18
After that your equation is 18=9x-18
Then your going to add 18 to each side so your equation should be 36=9x
Then devide each side by 9 so the answer will be x=4

3 0

3 years ago

According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health

katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74$

The probability is then

$P(X>65,000)=P(z>0.74)=0.22965$

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22$

The probability is then

$P(X>65,000)=P(z>1.22)=0.11123$

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?

To calculate the probability of earning less than $40,000, we can calculate the z-value:

$z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05$

The probability is then

$P(X$

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

$X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133$

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

8 0

3 years ago

In ΔCDE, \overline{CE}

abruzzese [7]

Answer:

$m\angle CDE=14^o$