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Nataly [62]
3 years ago
6

If f(x)=2x-9 what is f(5)

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0

Answer:

look at this figure to get answer

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PLEASE HELP!!! WILL REWARD BRAINLIEST!!!
jonny [76]

Answer:

The approximate monthly rate of growth is 1.24%

Step-by-step explanation:

we have the future value formula

F=P(1+r)^t

we have

r=16\%=16/100=0.16 ----> annual interest rate

so

F=P(1+0.16)^t

F=P(1.16)^t

Find the approximate monthly rate of growth

Remember that

1\ year=12\ months

so

Divide the number of periods t by 12

F=P(1.16)^{\frac{t}{12}}

Applying power rules property

F=P(1.16^\frac{1}{12})^t

F=P(1.0124)^t}

1.0124-1=0.0124

Convert to percentage

0.0124*100=1.24\%

therefore

The approximate monthly rate of growth is 1.24%

6 0
3 years ago
What is the value of n in the equation 1 (n – 4) – 3 = 3 - (2n+3)?
xxTIMURxx [149]

Answer:

n=7/3

Step-by-step explanation:

1 (n – 4) – 3 = 3 - (2n+3)

1. distribute the 1 on the left side and distribute the -1 on the right side

1n-4-3=3-2n-3

2. add like terms

1n-7=-2n

3. move n to one side and by itself

-7=-3n

4. divide -3 to get n alone. Both negatives cancel out each other

7/3=n

4 0
3 years ago
Read 2 more answers
Please help, I need help.<br><br>I don't understand.
Lana71 [14]

Find slope of both

#1

  • (11,2)
  • (22,4)

\\ \tt\hookrightarrow m=\dfrac{4-2}{22-11}=\dfrac{2}{11}=1.8

#2

  • (0,0)
  • (5,1)

\\ \tt\hookrightarrow m=\dfrac{1-0}{5-0}=\dfrac{1}{5}=0.2

Option C is correct

7 0
2 years ago
If the tank is then field to capacity how many half-gallon bottles how many cords will it make?
lukranit [14]

Answer:

Divide 12 by 4 first to figure out how many gallons are in each 1/4 of the tank. 

12/4=3

So if I added another 1/4 to the capacity:

It could hold 15 gallons. 

All you have to do to find how many half bottles can be filled is to times 15 by two since we are filling half gallon bottles.

15x2=30

30 bottles.

6 0
3 years ago
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
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