Answer:
Step-by-step explanation:⇔
∠B
∠D
are the measures but if you forgot to add the picture then... who knows
Suppose the length of the triangle is x, if the perimeter of the rectangle is 100 ft, the width of the rectangle will be (50-x) ft.
Area of rectangle will be:
A=length*width
A=x(50-x)
A=50x-x^2
at maximum area, dA/dx=0
thus
dA/dx=50-2x=0
solving for x we get
2x=50
x=25
thus for maximum area length=25 ft
the size of the width will be
50-x=50-25=25 ft
thus the maximum area will be:
25*25=625 sq. feet
Hello from MrBillDoesMath!
Answer:
+\- 10i
Discussion:
Fortunately, I can do this one in my sleep...... );
+\- sqrt(-100) =
+\- 10 i where i = sqrt(-1)
Thank you,
MrB
