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Kisachek [45]
3 years ago
9

MATH HELP PLZZZZZ!!! 10pts

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0
First i got the area which is : A= a+b divided by 2 x height 
=2.5+3.5 divided by 2 x 2= 6
Area = 6

To get the perimeter you just add all the sides together so: 3.5+2.5+2.5+2.5= 11
tester [92]3 years ago
4 0

Answer:

First i got the area which is : A= a+b divided by 2 x height  

=2.5+3.5 divided by 2 x 2= 6

Area = 6

To get the perimeter you just add all the sides together so: 3.5+2.5+2.5+2.5= 11

Step-by-step explanation:


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rewona [7]

i thinks its a little

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3 years ago
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A semicircle is cut out of a rectangular paperboard 24in long and 18n wide, as shown below. What is the perimeter of the paperbo
svet-max [94.6K]

Answer:

Perimeter of the paperboard that remains after the semicircle is removed = 94.26 in

Step-by-step explanation:

Watch the attached figure of how the semi circle is cut out of the rectangular paperboard.

Length = 24 in

Width = 18 in

Radius of the semi circle = Half of the width of the paperboard = \frac{18}{2} = 9 in

1) Circumference of the semi circle = π*radius

= 3.14*9

= 28.26 in

2) Perimeter of the paperboard that remains after the semicircle is removed

= Top + Left + Bottom + Right Circumference of the semi circle

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5 0
3 years ago
Please help me <br> can u explain how to do this
Ghella [55]

Answer:

x=41

Step-by-step explanation:

so since this is a right triangle you can use the Pythagorean Theorem to find the missing side. the two sides you know are 'a' and 'b' and the missing side is 'c'. the theorem says that:

a^2+b^2=c^2

so:

9^2 +40^2=c^2

solve for the exponents:

81 +1600=c^2

1681=c^2

and now, since 1681 is the missing side's length squared, we must find the square root of 1681, which is 41

hope this helps :)

7 0
3 years ago
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Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

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2 years ago
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Nookie1986 [14]
The solution is 15.
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3 years ago
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