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3 years ago

Need help with number 4 and number 6

Mathematics

1 answer:

Ann [662]3 years ago

3 0

Answer:

4. x=14.1 mi 6.x=8r3 km

Step-by-step explanation:

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WHAT IS THE MLA SURE OF ANGLE D PLZ HELP

Oliga [24]

AEB = CED = 180 - 45 - 14 = 121 deg
EDC = 180 - 121 - 27 = 32 deg

So angle D is 32 degrees

6 0

3 years ago

Expand d(d-4) PLEASE

gogolik [260]

Answer:

If you simplify it you get d^2-4d

Step-by-step explanation:

6 0

2 years ago

WILL MARK BRAINLIEST!!

Rudik [331]

Answer:

C = (A*P - 8.4Y -330T + 200I) / 100

Step-by-step explanation:

P = (8.4Y + 330T + 100C -200I ) / A

now we have to calculate completed passes C for given P, Y, T, I, A

A*P = 8.4Y + 330T -200I +100C

100C = A*P - 8.4Y - 330T + 200I

C = (A*P - 8.4Y -330T + 200I) / 100

I just solved the equation for C

5 0

2 years ago

The cost of 5 dresses and 2 belts is $48. The cost of 3 dresses and 2 belts is $32. Find the cost of a dress and a belt. Let x d

sergejj [24]

I think the answer is as

5 0

2 years ago

29. Find the height of the trapezoid. Use this height to find the area. (A =

harkovskaia [24]

Answer:

The area of the trapezium is 168

Step-by-step explanation:

Area of a Trapezoid

Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

$\displaystyle A=\frac{b_1+b_2}{2}h$

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

$10^2=EC^2+BC^2$

The side BC can be found as half the difference of the bases:

$BC=\frac{27-15}{2}=6$

Solving for EC:

$EC^2=10^2-6^2=100-36=64$

$EC=\sqrt{64}=8$

Now we have the height, calculate the area:

$\displaystyle A=\frac{15+27}{2}*8$

$\displaystyle A=\frac{42}{2}*8$

A = 168

The area of the trapezium is 168

5 0

2 years ago

Need help with number 4 and number 6​

Need help with number 4 and number 6