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3 years ago

Simplify 3 x n x p x6

Mathematics

2 answers:

Marina86 [1]3 years ago

8 0

Answer:

18np

Step-by-step explanation:

3*n*p*6

3n*p*6

3np*6

18np

vichka [17]3 years ago

7 0

Answer:

Step-by-step explanation:

3*n*p*6 = 18np

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If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

3 years ago

Find the ratio. Sam ran 3520 feet in 20 minutes.

Rufina [12.5K]

3520:20 should be correct

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3 years ago

Read 2 more answers

Does taking ginkgo tablets (i.e., and extract from a tree species) twice a day provide significant improvement in mental perform

Dmitriy789 [7]

Answer:

D. These results do not provide good statistical evidence that taking ginkgo tablets twice a day provides some improvement in mental performance. If 200 tests are being performed at the 5% significance level, some are bound to show statistically significant results, even if the treatment does not have any effect. It is premature to draw statistical conclusions from this study in which the percentage of significant tests is about 5%.

Step-by-step explanation:

It is not right to just made a conclusive argument on a large population by considering the outcome of the analysis made on a sample of the population. In addition, based on the number of tests conducted with about 5% significance level, it is clear that this can not be used to draw the necessary conclusion.

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3 years ago

What is the least common multiple of 156 and 321

jekas [21]

Hello Hdolly81

Backup:

156: 2,2,3,13,

321: 3,107

2 * 2 * 3 * 13 * 107 = 16692

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3 years ago

What is the balance as a result of having a credit of $84 and a debit of $29

Aleks [24]

The answer is $113 because you add the money

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3 years ago