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Leni [432]
3 years ago
7

To estimate the average salary among people in a certain district, a marketing team obtains a simple random sample of 100 people

from that district. The team sets up the following approximate 90% confidence interval, using a normal estimate, for the unknown average salary (in dollars annually) of the district:
[41500,49750]

__________ Approximately 90% of the people in the district have a salary in the interval
__________ The procedure used to construct the interval works approximately 90% of the time.
_________For the normal estimate of 90% confidence to apply, the salary distribution in the population must be approximately normal.
Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0

Answer:

The interpretation is that we are 90% sure that the true average salary of the district is in this interval.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

The 90% confidence interval for the average salary of the district is  [41500,49750].

This means that we are 90% sure that the true average salary of the district is in this interval.

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The seventh grade students are having an end-of-year party in the school
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The complete statement is:

  • Determine the number of tables by dividing 754 by 6
  • If there is a remainder, the answer will need to be rounded.
  • There is a remainder, so 126 tables are needed.

<h3>How to determine the number of tables?</h3>

The given parameters are:

Students = 754

Student per table = 6

The number of tables is calculated as:

Table = Students / Student per table

This gives

Table = 754/6

Evaluate the quotient

Table = 125.7

Approximate

Table = 126

Hence, the complete statement is:

Determine the number of tables by dividing 754 by 6

If there is a remainder, the answer will need to be rounded.

There is a remainder, so 126 tables are needed.

Read more about quotient at:

brainly.com/question/629998

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6 0
1 year ago
Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
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Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
The student council wants to rent a chocolate fountain for an overnight dance-a-thon. Their budget allows them to spend a maximu
vekshin1
$125 is a "must budget" so it will be the constant in the inequality

The fountain is $30 per hour. If they spend x hours, then their budget for fountain will be
fountain = 30x

The inequality
Their budget is maximum $250, that means they are able to spend less than or equal to $250
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125 + 30x ≤ 250
<em>This is the inequality expression</em>
6 0
3 years ago
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Answer:

1/4

Step-by-step explanation:

25 people took a vitamin and still got the flu and the total number is 100 so the fraction is 25/100 which can be reduce to 1/4

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