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Gekata [30.6K]
3 years ago
6

13.

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

5 units

Step-by-step explanation:

An isosceles triangle is a triangle with two legs that have the same length. The perimeter of a triangle is the sum of the lengths of all sides of the triangle. Now taking this into account, we know that:

2L + B = 14 units

Where:

L is the measure of one leg

B is the measure of the base

Since two legs are the same and the base is 1 less, this means the measure of each leg would be:

B = L -1

Now we have two equations:

2L + B = 14 units

B = L- 1

We plug one equation into the other and make 1 equation:

2L + (L-1) = 14 units

Get rid of the parentheses:

2L + L - 1 = 14

Combine like terms:

3L - 1 = 14

Add 1 to both sides of the equation:

3L - 1 + 1 = 14 + 1

3L = 15

Divide both sides by 3:

3L/3 = 15/3

L = 5

So the length of a leg is 5 units

Let's check!

B = L - 1

B = 5 - 1

B = 4

Then we use that to solve for the perimeter:

2L + B

2(5) + 4

10 + 4 = 14

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san4es73 [151]


To work out the LCM, we need their prime factors. So:

2 is simple 2 x 1.

7 is also 7 x 1.

13 is also 13 and 1.

They all have in common "1" - so we keep that aside as 1 figure, rather than 3.

We still have the 2, 7 and 13 leftover.

We then multiply the 1 with the other figures.

So 1 x 2 x 7 x 13 is our answer.

Which is = 182.


Hope I helped:)


~FabSafxo

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Factor 2a2b3 - 14ab + 16a
zhuklara [117]

Answer:

2a(b^3 - 7b + 8)

Step-by-step explanation:

I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.

Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.

2a2b3 - 14ab + 16a

2(ab^3 - 7ab +8a)

2a(b^3 - 7b + 8)

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3 years ago
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tia_tia [17]

Answer:

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Step-by-step explanation:

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Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
3 years ago
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