All categories

3 years ago

What is 129.392 rounded to nearest Ten?

Mathematics

2 answers:

vesna_86 [32]3 years ago

7 0

It’s 129.4 have a good day and get an a

Stels [109]3 years ago

6 0

$\huge\bold\color{purple}{Answer:}$

====================================

Explanation:

To round 129.392 to the nearest tenth consider the hundredths’ value of 129.392, which is 9 and equal or more than 5. Therefore, the tenths value of 129.392 increases by 1 to 4.

129.392 rounded to the nearest tenth = 129.4

 $\huge\bold\color{purple}{Hope \: it \: helps!}$ 

You might be interested in

A construction company recently built a thirty-story building on a lakefront in China. Architects and engineers designed the bui

STALIN [3.7K]

Answer:

15 days

Step-by-step explanation:360/24=15

4 0

3 years ago

Read 2 more answers

A flock of birds was flying around a tree. When they landed, three birds to a branch, no branches were left and one bird had to

trapecia [35]

Answer: 5 branches and 16 birds.

Step-by-step explanation:

If the number of birds is B, and the number of branches is N.

First we have the equation:

B = 3*N + 1

(3 birds per branch + 1 that was flying around)

for the second equation we have:

B = 4*(N - 1)

(4 birds per branch, but one branch had no birds on it, so there are N -1 branches used)

now we can write:

3*N + 1 = 4*(N - 1)

3*N + 1 = 4*N - 4

4 + 1 = 4*N - 3*N

5 = N

So we had 5 branches, now we can replace it in one of the equations and find the number of birds.

B = 3*N + 1 = 3*5 + 1 = 16

6 0

3 years ago

Read 2 more answers

7th question help please

vaieri [72.5K]

Surface area of the pyramid= 4*(area of the triangle) + area of the square

Area of the triangle = (1/2)*base*height=(1/2)*5*5= 25/2 in²
Area of the square = 5*5 =25 in²

Surface area of the pyramid = 4*(25/2) + 25=2*25 + 25=75 in²

3 0

3 years ago

Read 2 more answers

10. Which expression is represented by the model below? + o

galben [10]

I remember doing this one and its c

5 0

2 years ago

A cylinder shaped can needs to be constructed to hold 600 cubic centimeters of soup. The material for the sides of the can costs

PSYCHO15rus [73]

Answer:

the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

Step-by-step explanation:

since the volume of a cylinder is

V= π*R²*L → L =V/ (π*R²)

the cost function is

Cost = cost of side material * side area + cost of top and bottom material * top and bottom area

C = a* 2*π*R*L + b* 2*π*R²

replacing the value of L

C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²

then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then

dC/dR = -2*a*V/R² + 4*π*b*R = 0

4*π*b*R = 2*a*V/R²

R³ = a*V/(2*π*b)

R= ∛( a*V/(2*π*b))

replacing values

R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm

then

L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm

therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm

5 0

3 years ago

What is 129.392 rounded to nearest Ten?​

What is 129.392 rounded to nearest Ten?