Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
These are transformations. One thing to remember is that only a sign change (like a negative sign on the new function) will change the direction in which the parabola opens.
Here, going from f(x) to 1/2 * f(x) has no sign change, so the parabola will open in the same direction as before. Eliminate A and C.
Vertical transformations are those that are done to the entire function, as opposed to horizontal transformations which are done only on the x. Here, since we're multiplying 1/2 to f(x), we have a vertical transformation.
There are different transformations. The one here would be a vertical shrink by a factor of 1/2. Vertically shrinking a function is basically the same as compressing it, which would make it wider.
The answer is thus D.
Answer:
144
Step-by-step explanation:
12x12=144-1=143+1=144
Hope this helps!
In general, the most probable distribution is in the ratio of the respective types, namely
Number of blue tails
=12*(53/(53+40))
=6.84
To check between 6 or 7, we use the hypergeometric distribution:
P(B=6)
=C(40,6)C(53,6)/(C(93,12)
=3838380*22957480/416579843773639
=0.211530
P(B=7)
=C(40,5)C(53,7)/(C(93,12)
=658008*154143080/416579843773639
=65563917120/269282381237
=0.243476
Hence the most probable number of blue tail fishes is 7
Note: it would be prudent to calculate P(B=8)=0.194443 to show that P(B=7) is indeed the highest value.
For this question, let's use algebra!
<u>2.5 miles</u> = <u>50 minutes</u>
1 mile x minutes
x minutes = 50 x 1 ÷ 2.5
x minutes = 20
Hope this helps!
