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34kurt
4 years ago
8

Tracy recieves payments of $X at the end of each year for n years. The present value of her annuity is 493. Gary receives paymen

ts on $3X at the end of each year for 2n years. The present value of his annuity is $2,748. Both present values of calculated wit the same annual effective interest rate.
Find
vn
.
Mathematics
1 answer:
vladimir1956 [14]4 years ago
6 0

Answer:

v = 1/(1+i)

PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493

PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748

PV(G)/PV(T) = 2748/493

{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493

3[1-v^(2n)]/(1-v^n) = 2748/493

Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)

3(1 + v^n) = 2748/493

1 + v^n = 2748/1479

v^n = 1269/1479 ~ 0.858

Step-by-step explanation:

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2 years ago
Evaluate the following expression when x = 3 and y = 4:
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5 0
4 years ago
The revenue R you receive for selling pizza slices depends on the price p that you charge per slice and is modeled by R =-16p
sp2606 [1]

Answer:

p \geq 0

Step-by-step explanation:

Given

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Required

Determine the domain of the function

To do this, we need to solve for the vertex, p of the function

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Given the the general form of a quadratic function is:

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By comparison, we have:

a = -16    b =80    c = 5

So:

p= \frac{-b}{2a}

p = \frac{-80}{-16 * 5}

p = \frac{-80}{-80}

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8 0
3 years ago
A running track in the shape of an oval is shown. The ends of the track form semicircles. A running track is shown. The left and
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5 0
3 years ago
Read 2 more answers
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