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3 years ago

Find the interest due on $800 at 12% for 120 days

Mathematics

2 answers:

icang [17]3 years ago

8 0

Answer:

The simple interest after 120days at 12% is

$31.56

Step-by-step explanation:

Step one :

We know that the simple interest formula is

SI=(P*r*t)/100

Where p= principal

r= rate

t= time

Given data

P=$800

r=12%

t=120days to years 0.3287

Substituting this value in the simple interest equation we have

SI={800*12*0.3287}/100

SI=9600*0.3287

SI=3156.1644/100

SI=$31.56

slamgirl [31]3 years ago

3 0

Answer:

32.00

Step-by-step explanation:

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Which of the following is equal to the rational expression when x -2 or -1? x^2-4/(x+2)(x+1)

Orlov [11]

Answer:

(x+2)(x+1)

Step-by-step explanation:

Assuming im interpreting this correctly, it should be (x+2)(x+1), since if you plug in -2 and -1, it will give you 0, which is the answer.

8 0

3 years ago

The half life of silicone-32 is 710 years. If 30 grams is present now, how much will be present in 300 years?

Irina18 [472]

Answer:

22.38 g of silicone-32 will be present in 300 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know:

The initial quantity of silicone-32 is 30 g.
The time elapsed is 300 years.
The half life of silicone-32 is 710 years.

So, to find the quantity of silicone-32 remaining we apply the above equation

$N(t)=30\left(\frac{1}{2}\right)^{\frac{300}{710}}=30\left(\frac{1}{2}\right)^{\frac{30}{71}}\approx22.38 \:g$

22.38 g of silicone-32 will be present in 300 years.

7 0

3 years ago

Select the reason why these triangles are similar. if they are not select no similar

lana66690 [7]

Answer:

SAS

Step-by-step explanation:

well there exactly ths same you just add what ever inside and subtract forn 180 which is an angle

6 0

3 years ago

Read 2 more answers

NO LINKS!!!!

DedPeter [7]

9514 1404 393

Answer:

3. vertical stretch by a factor of 2; shift right 1 and down 1

4. shift left 4 and up 4 (no stretch or shrink)

Step-by-step explanation:

The vertex form equation is ...

y = a(x -h)^2 +k

It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.

Compare the the given equations to the above form to see the transformations.

3. (a, h, k) = (2, 1, -1) ⇒ vertical stretch by a factor of 2; shift right 1, down 1

4. (a, h, k) = (1, -4, 4) ⇒ no vertical stretch; shift left 4, up 4

6 0

3 years ago

A baseball team had $1,000 to spend on supplies. The team spent $185 on a new bat. New baseball cost $4 each. The inequality 185

Marta_Voda [28]

This question is incomplete

Complete Question

A baseball team had $1,000 to spend on supplies. The team spent $185 on a new bat. New baseballs cost $4 each.

The inequality 185 + 4b ≤ 1,000 can be used to determine the number of new baseballs (b) that the team can

purchase. Which statement about the number of new baseballs that can be purchased is true?

A. The team can purchase 204 new baseballs.

B. The minimum number of new baseballs that can be purchased is 185.

C. The maximum number of new baseballs that can be purchased is 185.

D. The team can purchase 185 new baseballs, but this number is neither the

maximum nor the minimum.

Answer:

D. The team can purchase 185 new baseballs, but this number is neither the maximum nor the minimum.

Step-by-step explanation:

The first step would be to solve the given equation:

185 + 4b ≤ 1000

4b ≤ 1000 - 185

4b ≤ 815

Divide both sides by 4

b ≤ 203.75

The maximum amount of baseballs the team can buy is 203. This means that they can buy 203 or less than that amount.

Of all the options give, option D is the correct option because the team can purchase 185 new baseballs, but this number is neither the maximum nor the minimum.

The maximum number of ball they can buy is 203 balls and the minimum is zero.

8 0

3 years ago