Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Answer:
k = 575
Step-by-step explanation:
let d be distance and h time.
Given d varies directly as h then the equation relating them is
d = kh ← k is the constant of variation
To find k use the condition d = 2875, h = 5, then
2875 = 5k ( divide both sides by 5 )
k = 575
for the first one set 3y+y=180 and y+x=180
the second one set w+y=180, 42+x=180, y+20=180, and 87+v
Answer:
No
Step-by-step explanation:
To find out if (4,10) is a solution to the system, we plug in the values of x and y into each equation.
1:
2:
As you can see, (4,10) only satisfies ONE equation, not both. Therefore, the answer is no, it's not a solution.
