Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
11 centimeters is the length of the launch pad
Answer:
x-int: (-1, 0), (-11, 0)
y-int: (0, 11)
Step-by-step explanation:
To find x-int, set equation equal to 0:
x² + 12x + 11
(x + 1)(x + 11)
x = -11, -1
To find y-int, set <em>x</em> = 0
f(0) = 0² + 12(0) = 11
f(0) = 11
Answer:
Step-by-step explanation:
c
S(20)=
5*20-2=100-2=98