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Sedaia [141]
3 years ago
6

If the simple interest on $6,000 for 4 years is $1,920, then what is the interest rate?

Mathematics
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

8 percent

Step-by-step explanation:

Since the formula for interest rate is the original money, the amount of years, and the inetrest rate multiplied together, we could plug it into an equation. 6000 times 4 times the ineterest rate is equal to 1920. 6000 times 4 is 24000. 1920 divided by 24000 is equal to 0.08 or 8 percent.

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HELP PLZ<br> ASAP thanks!
serious [3.7K]

Answer:

(-9, 0)

Step-by-step explanation:

Look at the point in your answer. Its y-coordinate is zero. The x-intercept is where the line intersects the x-axis. At the x-axis, every point has y-coordinate zero. Set y equal to zero and solve for x.

-2x + (1/2)y = 18

-2x + (1/2)(0) = 18

-2x = 18

x = -9

Answer: (-9, 0)

4 0
3 years ago
Sleep deprivation, CA vs. OR, Part I. According to a report on sleep deprivation by the Centers for Disease Control and Preventi
vlabodo [156]

Answer:

0.008±0.0095=(-0.0015,0.0175)

Step-by-step explanation:

In this case we must use the formula to calculate the confidence interval for the difference between two proportions given by inferential statistics. The formula to calculate both limits of the interval is as it follows:

(p_{1}-p_{2} )+\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}}  } \\(p_{1}-p_{2} )-\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}}  }

Where:

p_{1}: proportion of population one (in our case: Oregon residents who reported insufficient rest or sleep)

p_{2}: proportion of population two (in our case: California residents who reported insufficient rest or sleep)

z_{(∝/2)}: quantile of the normal distribution with α/2 probability (in our case, from the standard normal table we have 1.96 for a confidence level of 95%)

n_{1}: sample size for population one (in our case, sample of Oregon residents)

n_{2}: sample size for population two (in our case, sample of California residents)

Now, with our data we have:

p_{1}=0.088  

p_{2}=0.08  

z_{(∝/2)}=1.96  

n_{1}=4,691  

n_{2}=11,545  

Therefore, we obtain:

(0.088-0.08)+1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} } \\(0.088-0.08)-1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} }

Finally, the result for our interval:

0.008+0.0095=(-0.0015,0.0175)

According to the result we can say with a 95% confidence, that the proportion of Oregon residents with sleep deprivation issues is the same as the proportion of California residents. The reason for this is that 0 (zero) is contained within the interval.

7 0
3 years ago
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Answer:

-4 and 0

Step-by-step explanation:

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Step-by-step explanation:

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The answer is 2√19 I think
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