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Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.
If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.
We multiply the probabilities of these two events to find the probability of them both happening.
1/2×25/51=25/102
The probability of picking two red cards in a row is 25/102 or around 24.5%.
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Answer:
n = -6
Step-by-step explanation:
2 ( n + 5 ) = -2
First, solve the brackets.
2n + 10 = -2
Now take 10 to the right side.
2n + 10 -10 = -2 - 10
2n = -12
Then divide both sides by 2.

And now you'll the value of n.
n = ( -6 )
The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
Learn more about the percentage here:
brainly.com/question/92258
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Answer:
x^2+2x-5 - 1/x
Step-by-step explanation:
f(x)=1/x
g(x)=x^2+2x-5
(g-f)(x) = x^2+2x-5 - 1/x