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Nimfa-mama [501]
3 years ago
7

In triangle QRS, QR = 2x + 5, RS = 3x - 1, and SQ = 5x. Solve for x.

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0
The answer to you question is x=3/4
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Write equation for the line with a slope "undefined" and has the same x-intercept as x−y−1=0
Mariana [72]

Answer:

Step-by-step explanation:

Lines with undefined slopes are perfectly vertical, of the form "x = ". A line with "the same x-intercept" as the given line that has an undefined slope will be the line that we want. I know that sounds confusing; we'll work through it then I'll explain it better. In order to find the x-intercep of the given line, solving it for y will make it a bit easier to "see". Therefore,

-y = -x + 1 and

y = x - 1. The x-intercept exists when y = 0, so setting y equal to 0 and solving for x:

0 = x - 1 and

1 = x. That's the x-intercept. It's also the line that we want that has an undefined slope, because "x = " lines are lines vertical lines and vertical lines have undefined slopes.

x = 1 is the line you want.

8 0
2 years ago
Need help with all them, state how you know also<br><br> Triangle Congruency
nata0808 [166]

Answer

where is the pdf?

Step-by-step explanation:

8 0
2 years ago
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Describe what solving a trigonometric equation is.
AleksAgata [21]
That's an awfully broad question.  Could you not be more specific?

A basic example:  Suppose you are told that sin theta = 1/2.  Solving this equation would require finding the measure of the angle theta.  In this case the answer would be "30 degrees," or "pi/6 radians."

6 0
3 years ago
The store,s rectangular floor is 42 meters long and 39 meters wide. How many square meters of flooring do they need? Use estimat
Helga [31]
We have to find the area of the floor in order to know how many square meters of flooring they need.

The area of the floor is:
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8 0
2 years ago
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100 POINTS AND BRAINLIEST
zysi [14]

Answer:

8 square units and \frac{40}{3} square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor \frac{1}{3}, then

\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.

2. Triangles ABC and DBE are similar with scale factor \frac{2}{3}, then

\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.

3. Thus, the area of the quadrilateral DFGE is

A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.

and the area of the quadrilateral ADEC is

A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.

4 0
3 years ago
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