![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
5 years because when you divide 90 by 18 to get how many years it takes the tree to grow to 90 inches tall, you get 5.
Answer:
100feet
Step-by-step explanation:
Given the height reached by a dolphin expressed by the equation is h = -16t^2 + 80t. At maximum height, the velocity is zero, hence;
v(t) = dh/dt = -32t + 80
0 = -32t + 80
32t = 80
t = 80/32
t = 2.5secs
Substitute t = 2.5 into the height formula h = -16t^2 + 80t
h = -16(2.5)^2 + 80(2.5)
h = -100+200
h = 100feet
Hence the maximum height the dolphin jumps is 100feet
Answer:
The range of the graph is:
-3 ≤ y ≤ 3
Hence, option (B) is correct.
Step-by-step explanation:
We know that the range of a function is the set of values of the dependent variable 'y' for which a function is defined.
From the given graph, it is clear that the graph goes down at y=-3 and then goes up to y=3 and then goes down again.
In fact, this indicates that the range of the graph lies between y=-3 to y=3
Therefore, the range of the graph is:
-3 ≤ y ≤ 3
Hence, option (B) is correct.
