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sergeinik [125]
3 years ago
12

(3 - i) + (1 - 2i) =

Mathematics
1 answer:
eimsori [14]3 years ago
5 0
(3 - i) + (1 - 2i)
= 3 + 1 - i - 2i
= 4 - 3i
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6City A is located in a valley 15 meters below sea level, and City B is located 43 meters above sea level. What is the differenc
nirvana33 [79]

Answer:

28

you just subtract the 43 and 15

8 0
3 years ago
Quintin’s monthly budget is shown on the table below. Quintin wants to start putting $50 in savings each month. If he does, how
NemiM [27]

Answer:

what is quintin's monthly salary

please post full question

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3 years ago
Listed below are the commissions earned ($000) last year by a sample of 15 sales representatives at Furniture Patch Inc.
Alexeev081 [22]

Answer:

Mean= $21.5067

Median = $15.8

Standard deviation= $19.02

Coefficient of skewness= $0.8991

Step-by-step explanation:

Mean =( $4.0 +$6.0 +$7.4+ $10.6 +$12.5+ $13.6+ $15.4+ $15.8 +$16.8

+$17.4+ $19.1 +$22.3+ $37.1 +$43.2 +$81.4)/15

Mean =$ 322.6/15

Mean= $21.5067

Median= middle number

Median = $15.8

Variance=( ($4.0-.$21.5)²+( $6.0. -.$21.5)²+( $7.4 -.$21.5)²+( $10.6 -.$21.5)²+( $12.5 -.$21.5)²+( $13.6. -.$21.5)²+ ($15.4 -.$21.5)²+( $15.8 -.$21.5)²+ ( $16.8 -.$21.5)²+ ($17.4-.$21.5)² +($19.1 -.$21.5)²+ ($22.3 -.$21.5)²+ ($37.1 -.$21.5)²+ ($43.2-.$21.5)²+( $81.4-.$21.5)²)/15

Variance=$ 5424.79/15

Variance=$ 361.65

Standard deviation= √ variance

Standard deviation= √361.65

Standard deviation= $19.02

Coefficient of skewness

=3( mean-median)/standard deviation

= 3(21.5-15.8)/19.02

= 3(5.7)/19.02

= 17.1/19.02

Coefficient of skewness= 0.8991

5 0
3 years ago
Can someone help please. Im stuck.
Fantom [35]

Answer:

the answer is B.

Step-by-step explanation:

100*20 + 1/2*(60-20)*(100 - 12)

=2000 + 1/2*40*88

=3760

8 0
3 years ago
A chemist measures 8 grams of a substance that
Greeley [361]

Answer:

y(t) =8 (b)^t Where b is the decay rate for this case. Using the condition given we have:

4 = 8 b^6

\frac{1}{2}= b^6

b = (\frac{1}{2})^{1/6}

And our model would be given by:

y(t) = 8 (\frac{1}{2})^{t/6}

And replacing the value of t=15 we got:

y(15) = 8 (\frac{1}{2})^{15/6} = 1.414 grams

Step-by-step explanation:

For this case since the half life is 6 hours we have the following condition:

y(6) = \frac{1}{2}A_o

Where A_o=4 is the initial amount

Our model for this case is given by this expression:

y(t) =8 (b)^t Where b is the decay rate for this case. Using the condition given we have:

4 = 8 b^6

And solving for b we got:

\frac{1}{2}= b^6

And solving for b we got:

b = (\frac{1}{2})^{1/6}

And our model would be given by:

y(t) = 8 (\frac{1}{2})^{t/6}

And replacing the value of t=15 we got:

y(15) = 8 (\frac{1}{2})^{15/6} = 1.414 grams

5 0
3 years ago
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