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sergeinik [125]
3 years ago
12

(3 - i) + (1 - 2i) =

Mathematics
1 answer:
eimsori [14]3 years ago
5 0
(3 - i) + (1 - 2i)
= 3 + 1 - i - 2i
= 4 - 3i
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The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater
Sergio039 [100]

Answer:

A.) Function 1 has the larger maximum at (4, 1).

Step-by-step explanation:

No step-by-step explanation, nobody pays attention to them anyway.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
3 years ago
Please help! i dont understand
kvv77 [185]

QUESTION 1

The given inequality is  

y\leq x-3 and y\geq -x-2.

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

-2\leq 3-3 and -2\geq -3-2.

-2\leq 0:True and -2\geq -5:True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is  

y\:>\:-3x+3 and y\:>\: x+2.

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

4\:>\:-3(1)+3 and 4\:>\: 1+2.

4\:>\:0:True and 4\:>\: 3:True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is  

y\leq 3x-6 and y\:>\: -4x+2.

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

-2\leq 3(0)-6 and -2\:>\: -4(0)+2.

-2\leq -6:False and -2\:>\:2:False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is  

2x-y\: and x+y\:>\:-1.

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

2(0)-3\: and 0+3\:>\:-1.

-3\::True and 3\:>\:-1: True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is  

y\:>\:2x-3 and y\:.

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

0\:>\:2(-3)-3 and 0\:.

0\:>\:-9;True and 0\::True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0
3 years ago
The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the
erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes  is 0.4786.

Step-by-step explanation:

The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, <em>β</em> = 19 minutes.

The random variable <em>X</em> follows an Exponential distribution with parameter \lambda=\frac{1}{\beta}=\frac{1}{19}.

The probability distribution function of <em>X</em> is:

f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...

Compute the value of the event (<em>X</em> > 14) as follows:

P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786

Thus, the probability that the wait time is greater than 14 minutes  is 0.4786.

7 0
3 years ago
A researcher asks random samples of residents of two separate counties as to whether they had purchased organically grown food i
Leni [432]

Answer:

2 proportions z test

The two populations are named as residents from the first county and residents from the second county.

Step-by-step explanation:

This is testing hypothesis about the difference between two proportions.

When the proportions are tested if they are the test statistic

z= ( p^1-p^2)- (p1-p2) / √p₁q₁/n₁ + p₂q₂/ n₂

where p^1 is the proportion of success in the first sample and   p^2 of size n₁   is the proportion of success in the second sample of size n₂ with unknown proportions of successes p1 and p2 respectively.

When the sample sizes are sufficiently large

z= ( p^1-p^2)- (p1-p2) / √p₁q₁/n₁ + p₂q₂/ n₂ is approximately standard normal.

The two populations are named as residents from the first county and residents from the second county.

7 0
3 years ago
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