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3 years ago

7

Need help with question please

1 answer:

viktelen [127]3 years ago

6 0

Answer:

The answer is x = -7.7 ans x = -1.3

Step-by-step explanation:

Here is the work I did. I used the quadratic formula. Sorry about my bad handwriting.

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Which of the following is the equation of the line that is parallel to y=35x+8 y = 3 5 x + 8 and goes through point (-10,4)?

xeze [42]

Slope-intercept form of a line is y=mx+b.

Where m= slope and b= y-intercept.

First step is to compare the given equation y=35x+8 with the above equation to get the value of m.

After comparing the two equations we will get m=35.

Slope of paralle lines always equal which means slope of a line which is parallel to the above line will also be 35.

Now the line is passing through (-10,4).

Point slope form of a line is :

$y-y_{1} =m(x-x_{1} )$

Next step is to plug in m=35, x1=-10 and y1=4 in the above equation. So,

y-4=35(x-(-10)

y-4=35(x+10)

y-4=35x+350

y=35x+350+4

y=35x+354.

So, the equation of the line is y=35x+354.

4 0

3 years ago

Please help i need this grade

Arlecino [84]

C... all are correct

7 0

3 years ago

Factor -12n-24 Pleasee helppp

Novosadov [1.4K]

-12 n - 24 = -12 (n+2)

-12 (n+2) is the answer

7 0

3 years ago

Read 2 more answers

Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

So

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

So

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

So

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

3 years ago