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Alex17521 [72]
4 years ago
11

Which expression is equivalent to *picture attached*

Mathematics
1 answer:
STALIN [3.7K]4 years ago
7 0

Answer:

\frac{35(1 + 35)}{2}

Step-by-step explanation:

Given:

The attached

Required

Find the equivalent expression

The interpretation of is to add the sequence:

n = 1,2,3,......35

This can be done using the following formula (Sum of n terms of an AP)

S_n = \frac{n}{2}(T_1 + T_n)

Where n is the number of terms from 1 to 35; n = 35

T1 is the first term; T_1 = 1

Tn is the last term; T_n = 35

S_n = \frac{n}{2}(T_1 + T_n) becomes

S_n = \frac{35}{2}(1 + 35)

S_n = \frac{35(1 + 35)}{2}

From the list of given options;

Option A is correct

\frac{35(1 + 35)}{2}

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Dan buys a car for £2200.
KatRina [158]

Answer:

The worth of the car after 6 years is £2,134.82

Step-by-step explanation:

The amount at which Dan buys the car, PV = £2200

The rate at which the car depreciates, r = -0.5%

The car's worth, 'FV', in 6 years is given as follows;

FV = PV \cdot \left ( 1 + \dfrac{r}{100} \right )^n

Where;

r = The depreciation rate (negative) = -0.5%

FV = The future value of the asset

PV = The present value pf the asset = £2200

n = The number of years (depreciating) = 6

By plugging in the values, we get;

FV = 2200 \times \left ( 1 + \dfrac{-0.5}{100} \right )^6 \approx 2,134.82

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))

8 0
3 years ago
A supplier of a certain car parts chain of stores wants to estimate the average length of time car owners plan to keep their car
____ [38]

Answer:

The 99% confidence interval for the average length of time all car owners plan to keep their cars is between 3.85 years and 10.55 years.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{6.5}{\sqrt{25}} = 3.35

The lower end of the interval is the sample mean subtracted by M. So it is 7.2 - 3.35 = 3.85 years

The upper end of the interval is the sample mean added to M. So it is 7.2 + 3.35 = 10.55 years

The 99% confidence interval for the average length of time all car owners plan to keep their cars is between 3.85 years and 10.55 years.

7 0
3 years ago
if venus is 30.9 mi farther from the sun than mercury, the the earth is 23.6 mi farther from the sun than venus. when the total
luda_lava [24]

Answer: The mercury is 38 mi far from sun.

Step-by-step explanation:

Let x denotes the distance ( in mi )between the Sun and Mercury .

Distance from Venus to Sun = x+30.9

Distance from Earth = x+30.9+ 23.6 =x+30.9+ 23.6 =x+54.5

When the total of the distances for these plants from the sun is 199.4 mi.

According to the given statements , we have

x+x+30.9+x+54.5=199.4

3x+85.4=199.4

3x=199.4-85.4=114

x=38 [Divide both sides by 3]

Hence, the mercury is 38 mi far from sun.

6 0
3 years ago
In triangle abc the measure of angle a = measure of angle b + 30, the measure of angle c = measure of angle b + 60. find the mea
Morgarella [4.7K]
B 60.5
a 90.5
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follow the steps in the picture

4 0
4 years ago
What fractions are equivalent to 1/3?
ExtremeBDS [4]

Answer:

#markasbrainliest

1/3

=

2/6

=

3/9

=

4/12

=

5/15

=

6/18

=

7/21

=

8/24

=

9/27

=

10/30

=

11/33

=

12/36

=

13/39

=

14/42

=

15/45

=

16/48

=

17/51

=

18/54

=

19/57

=

20/60

=

21/63

=

22/66

=

23/69

=

24/72

=

25/75

=

26/78

=

27/81

=

28/84

=

29/87

=

30/90

=

31/93

=

32/96

=

33/99

=

34/102

=

35/105

=

36/108

=

37/111

=

38/114

=

39/117

=

40/120

=

41/123

=

42/126

=

43/129

=

44/132

=

45/135

=

46/138

=

47/141

=

48/144

=

49/147

=

50/150

=

51/153

=

52/156

=

53/159

=

54/162

=

55/165

=

56/168

=

57/171

=

58/174

=

59/177

=

60/180

=

61/183

=

62/186

=

63/189

=

64/192

=

65/195

=

66/198

=

67/201

=

68/204

=

69/207

=

70/210

=

71/213

=

72/216

=

73/219

=

74/222

=

75/225

=

76/228

=

77/231

=

78/234

=

79/237

=

80/240

=

81/243

=

82/246

=

83/249

=

84/252

=

85/255

=

86/258

=

87/261

=

88/264

=

89/267

=

90/270

=

91/273

=

92/276

=

93/279

=

94/282

=

95/285

=

96/288

=

97/291

=

98/294

=

99/297

=

100/300

3 0
3 years ago
Read 2 more answers
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