Question

A human society has 73 dogs and cats to be adopted. the number of cats is 10 more than twice the number of dogs. Write a system of linear equations that represent this situation. How many of each animal is up for adoption?

Answer 1

Total: 73
dogs: x
cats: 2x+10

2x+10+x=73
3x+10=73
3x=63
x=21

dogs: x
dogs: 21

cats: 2x+10
cats: 52

Check answer:
cats+dogs=73
52+21=73

There's no need for a system of linear equations if you were to solve a real life problem like this. In calculus, they don't give a rat about HOW you get your answer to an easy algebra 1 equation, as long as you used one of the correct methods and got the right answer.

Best of luck my friend. :)