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solong [7]
3 years ago
15

The manufacturer of the ColorSmart-5000 television set claims 95 percent of its sets last at least five years without needing a

single repair. In order to test this claim, a consumer group randomly selects 420 consumers who have owned a ColorSmart-5000 television set for five years. Of these 420 consumers, 303 say their ColorSmart-5000 television sets did not need a repair, whereas 117 say their ColorSmart-5000 television sets did need at least one repair. (a) Find a 99 percent confidence interval for the proportion of all ColorSmart-5000 television sets that have lasted at least five years without needing a single repair.
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0

Answer: (0.665 , 0.777)

Step-by-step explanation:

Given : Sample size of consumers: n=420  ;

Number of consumers say their ColorSmart-5000 television sets did not need a repair=303

The the sample proportion for consumers say their ColorSmart-5000 television sets did not need a repair : \hat{p}=\dfrac{303}{420}\approx0.721

Significance level : \alpha:1-0.99=0.01

Critical value = z_{\alpha/2}=\pm2.576

The confidence interval for population proportion is given by :_

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

i.e.  0.721\pm (2.576)\sqrt{\dfrac{0.721(1-0.721)}{420}}

\approx0.721\pm 0.056=(0.721-0.056,0.721+0.056)\\\\=(0.665\ ,\ 0.777)

Hence,  a 99 percent confidence interval for the proportion of all ColorSmart-5000 television sets that have lasted at least five years without needing a single repair = (0.665 , 0.777)

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Since CAB = 90º, this is a right triangle.

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Length of BC:

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In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So

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