we know its diameter is 12, thus its radius must be half that, or 6.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=6 \end{cases}\implies A=\pi 6^2\implies A=36\pi \implies A\approx 113.097](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%206%5E2%5Cimplies%20A%3D36%5Cpi%20%5Cimplies%20A%5Capprox%20113.097)
ANSWER
9
EXPLANATION
We want to find the distance between the points (3, -5) and (-6, -5).
The given points have the same y-coordinates .
This means it is a horizontal line.
We use the absolute value method to find the distance between the two points.
We find the absolute value of the distance between the x-values.
The distance between the two points is
|3--6|=|3+6|=|9|=9
How do you upload the pictures on here?
Neither of those work for that equation
Answer:
the answer is $864 pls give brainliest
Step-by-step explanation: