Answer:
Step-by-step explanation:
<em>As written</em>, you have an equation that cannot be solved algebraically.
(32^2)c = 8^c
1024c = 8^c
1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero
A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.
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If you mean ...
32^(2c) = 8^c
(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2
2^(10c) = 2^(3c) . . . . . . . simplify
10c = 3c . . . . . . . . . . . . . .log base 2
7c = 0 . . . . . . . . . . . . . . . subtract 3c
c = 0 . . . . . . . . . . . . . . . . divide by 7
(1)
given =
( cross- multiply )
10j = 54 ( divide both sides by 10 )
j = =
← in simplest form
(9)
let h be the hours worked daily , then
3h = 20 =
( divide both sides by 3 )
h = ÷ 3
= ×
=
= 6
She worked 6 hours each day
Answer:
1. 7
2. 100000000
Check the above picture
