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harina [27]
3 years ago
6

Can somebody please solve question 11 for me?

Mathematics
1 answer:
love history [14]3 years ago
6 0
1+tan^2(A) = sec^2(A) [Pythagorean Identities]

tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)


*see photo for complete solution*

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Whole numbers are written on cards and then placed in a bag. Tyra selects a single card, writes down the number. and then placed
wariber [46]
The tables shows that the relative frequencies for each number are very similar 0.19, 0.20 and 0.21.

That drives to tell that the outcomes appear to be equally like.

That means that the probabilities are uniform, so the answer is:
<span>The outcomes appear to be equally likely, so a uniform probability model is a good model to repersent the probabilities in Tyra's experiment.</span>
 

3 0
3 years ago
An insurance policy on an electrical device pays a benefit of 4000 if the device fails during the first year. The amount of the
lora16 [44]

Answer:

Expected benefit under this policy = $ 2694

Step-by-step explanation:

Given - An insurance policy on an electrical device pays a benefit of

            4000 if the device fails during the first year. The amount of the

            benefit decreases by 1000 each successive year until it reaches 0.

            If the device has not failed by the beginning of any given year, the

            probability of failure during that year is 0.4.

To find - What is the expected benefit under this policy ?

Proof -

Let us suppose that,

The benefit = y

Given that, the probability of failure during that year is 0.4

⇒Probability of non-failure = 1 - 0.4 = 0.6

Now,

If the device fail in second year , then

Probability = 0.6×0.4

If the device fail in third year, then

Probability = 0.6×0.6×0.4 = 0.6² × 0.4

Going on like this , we get

If the device is failed in n year, then

Probability = 0.6ⁿ⁻¹ × 0.4

Now,

The probability distribution is-

Benefit , x       4000       3000             2000            1000              0

P(x)                 0.4         0.6×0.4         0.6² × 0.4     0.6³ × 0.4     1 - 0.8704

                      (0.4)       (0.24)            (0.144)         (0.0864)       (0.1296)

At last year, the probability = 1 - (0.4+ 0.24+ 0.144+ 0.0864) = 1 - 0.8704

Now,

We know that,

Expected value ,

E(x) = ∑x p(x)

       = 4000(0.4) + 3000(0.24) + 2000(0.144) + 1000(0.0864) + 0(0.1296)

       = 1600 + 720 + 288 + 86.4 + 0

       = 2694.4

⇒E(x) = 2694.4 ≈ 2694

∴ we get

Expected benefit under this policy = $ 2694

5 0
2 years ago
Seven tenths of a number plus 14 is less than forty-nine
Virty [35]
7/10n + 14 = 49
7/10n = 35
n = 35 x 10/7
n = 50
7 0
3 years ago
Triangle EFG is an isosceles triangle with EG=EF. What is the approximate length of EF, and what is the approximate perimeter of
sineoko [7]

Answer:

B. The approximate length of EF is 4.47 units, and the approximate perimeter of triangle EFG is 12.94 units.

Step-by-step explanation:

First step is to determine the length of EF, since that will give us 2 sides of the triangle (since EG = EF).

From the diagram, we can easily make a rectangle triangle by dropping a vertical line from vertex E, let's name Z the meeting point of that line with the segment GF.  Then we have a rectangle triangle EZF with a height of 4 and a base of 2, of which EF is the hypotenuse. So...

EF² = 4² + 2² = 16 + 4 = 20

EF = √20 = 4.47

Now that we have EF, we also have EG:

EF = 4.47

EG = 4.47

GF = 4 (visible on the graph)

Perimeter = 4.47 + 4.47 + 4 = 12.94 units.

7 0
2 years ago
Read 2 more answers
Simplify the expression 6h+​(−8.7d​)−13+6d−3.3h.<br> 6h+​(−8.7d​)−13+6d−3.3h=
mezya [45]

Answer:

 -2.7d+2.7h-13

6 0
3 years ago
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