Can somebody please solve question 11 for me?
1 answer:
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
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<u>Find Common Denominator</u>
2: 2,4,6,8,10
4: 4,8,12,16,20
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