Mpuy each expression. 1) (5p2 – 3) + (2p2 – 3p3)
1 answer:
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Answer:
If D< 0, the roots of the quadratic equation will b complex.
Step-by-step explanation:
Let is the given quadratic equation.
So, if the Discriminant (D) = , the the equation will have only complex solutions.
Complex roots are represented in the form of
1. <u> x represents the X axis (real) co ordinate,</u>
<u>y represents the Y axis (imaginary) coordinate</u>
<u />
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2. Also, the graph of the with equation D < 0 NEVER CROSSES the X - axis, as there are no real roots of the equation, only complex roots.
3. Here. roots are always identical but are opposite in signs. Such pair or roots with opposite sign are called CONJUGATE PAIRS.
Answer:
Possible locker numbers for Selma are: 3, 5 and 29
Step-by-step explanation:
First of all, let us have a look at the definition of a prime number.
A <em>prime number</em> is a number which is divisible either by 1 or the number itself.
No other number divides the prime number other than 1 and the number itself.
Now, let us factorize the given number 435 and let us observe the what all possibilities are there.
Factorizing 145 further:
No further factors are possible.
Therefore 3, 5 and 29 are the prime factors of 435.
So, the answer is:
Possible locker numbers for Selma are: 3, 5 and 29