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SpyIntel [72]
3 years ago
8

Find the vector and parametric equations for the line through the point P(0, 0, 5) and orthogonal to the plane −1x+3y−3z=1. Vect

or Form: r
Mathematics
1 answer:
yulyashka [42]3 years ago
4 0

Answer:

Note that orthogonal to the plane means perpendicular to the plane.

Step-by-step explanation:

-1x+3y-3z=1 can also be written as -1x+3y-3z=0

The direction vector of the plane -1x+3y-3z-1=0 is (-1,3,-3).

Let us find a point on this  line for which the vector from this point to (0,0,5) is perpendicular to the given line. The point is x-0,y-0 and z-0 respectively

Therefore, the vector equation is given as:

-1(x-0) + 3(y-0) + -3(z-5) = 0

-x + 3y + (-3z+15) = 0

-x + 3y -3z + 15 = 0

Multiply through by - to get a positive x coordinate to give

x - 3y + 3z - 15 = 0

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Lady_Fox [76]

Answer:55 degrees

Step-by-step explanation:

So the two problems both ave TS which meant R is 20 and W is 25

and T is 10 and S is 10.

so

R 20 +

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7 0
3 years ago
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Gloria talked on her cell phone for 320 minutes the first month,243 minutes the second month,and 489 minutes the third month.Her
34kurt

Answer: \$175

Step-by-step explanation:

Since Gloria cannot pay for each minute talked but for packages of 200 minutes at the rate of $25 each, we have to make calculations according to these conditions as follows:

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Month 2:

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5 0
3 years ago
A seal dove 95 meters below the surface of the water to reach a fish. It traveled 18% of the total distance every second.
BlackZzzverrR [31]
95*18%
18%=0.18
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Now, multiply 17.1 by 5 = 85.5
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3 years ago
(−9+6.8−1.2)·(−0.49−0.51)
zmey [24]

Answer:

3.4

Step-by-step explanation:

(−9 + 6.8 − 1.2) · (−0.49 − 0.51)

(−3.4) · (−1)

3.4

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