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Aleks04 [339]
3 years ago
9

At the popular restaurant Fire Wok,

Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

55% = 11/20

Step-by-step explanation:

Marrrta [24]3 years ago
5 0

Answer:

The fraction of guests order the signature dish is 11/20

Step-by-step explanation:

Given Parameters

55% of guests order the signature dish

Required: The fraction of guests that ordered signature dish

The interpretation of the question is that we should convert the percentage of guests order the signature dish from percentage to fraction.

Let F represent the fraction of guests order the signature dish.

F = 55%

Convert to fraction

F = 55/100

Simplify by dividing the numerator and denominator by 5

F = (55÷5)/(100÷5)

F = 11/20

Hence, the fraction of guests order the signature dish is 11/20

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Can someone please help me solve this? <br><br> 2x+5y=-1 <br><br> -10x-25y=5
fredd [130]

this is system of equations

2x + 5y = -1   times this one by 5 to make the y's opposite

-10x -25y = 5

10x - 25y = -5  (this is it times by 5, now add them)

__________

0 + 0       = 0    

now since everything cancels and both sides are equal it has infinite solutions beaus they are actually the same line.  


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3 years ago
Triunghiul si elementele lui<br> Geometrie Clasa a -7 ex.11 p.154
Diano4ka-milaya [45]
<span>que debería haber escrito sólo el problema para nosotros tal vez podríamos haber ayudado a continuación .</span>
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3 years ago
Simplify 3(2x+4y-y) i need help with that please
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First simplify the like terms.
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3 years ago
K + 9 = 17<br><br> What does k value?<br> k=8<br> k=9<br> k=17 <br> k=26
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Answer:

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6 0
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Read 2 more answers
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
2 years ago
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