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Gennadij [26K]
3 years ago
5

Tell whether the rates are equivalent. 0.4 kilometer for every 15 minutes 0.6 kilometer for every 20 minutes

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0

Answer:

no they are not equivalent

Step-by-step explanation:

0.4/15 = 0.026

so for every minute they travel 0.026km

0.6/20 = 0.03

so for every minute they travel 0.03km

so they are not the same/equivalent

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The grass in Jamie's yard grew 16 centimeters in 10 days. It was growing at a constant rate. How many days did it take the grass
gulaghasi [49]

Answer:

1.6 cm

Step-by-step explanation:

16/10 = 1.6/1 so 1.6 cm in 1 day

7 0
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What is the value of the digit 9 in the attendance at the redskins vs titan game
Leokris [45]
9,345,654 million, if you want specific, tell me the number.
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Find the solution in the set W. 3 + x = x + 3
Keith_Richards [23]
Your answer will be 0.
Because if 3+x is the same as x+3. That is literally the same as 3+0=3. You can plug the 0 into the variable
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3 years ago
The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
2 years ago
La razon es la.división de dos números
morpeh [17]


Lo que se divide se llama dividendo, que se divide por el divisor, y el resultado se llama cociente. En el ejemplo, 20 es el dividendo, 5 es el divisor y 4 es el cociente.
4 0
3 years ago
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