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amid [387]
2 years ago
9

Plz help me and show work plz

Mathematics
1 answer:
Lerok [7]2 years ago
4 0

First rewrite the problem so you get \sqrt \frac{1}{4}

Then rewrite as \sqrt{1}\sqrt{4}

any root of 1 is one so

1/<em>\sqrt{4}</em>

1/\sqrt{ 2^{2}

Pull terms out from under the radical, assuming positive real numbers.

1 /2

<h2>so answer is 1/2</h2><h3>hope this helps</h3>

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Answer:

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Step-by-step explanation:

Given that:

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Unit Conversion formula:

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It is simple problem for the conversion of unit where we already know the value in one unit and the conversion formula as well.

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3 years ago
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Answer:

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Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

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It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F

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Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska  was 80°F below 0° F

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