F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5
Area of a rectangle = length (l) * width (w)
A = 30ft * 20ft
A = 600 sq ft
Now the width of a sidewalk that surroundeds it = 3 ft
so now the area of the rectangle with sidewalk= 30+3ft * 20+3ft
A = (33*23) ft
A = 759 sg ft
Area of the sidewalk = 759 - 600
A = 159 sq ft
Answer: yall boys go add me on tha gram
Step-by-step explanation:
Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
In order to find the answer, we need to do as follows:
Average no. of people per km^2 = total no. of people ÷ total no. of people
Average no. of people per km^2 = 1, 080, 264, 388 ÷ 2, 973, 190
Average no. of people per km^2 = 363.335134317
Now we need to round the answer to the nearest whole number. In this case, we will be rounding down as displayed below:
Average no. of people per km^2 = 363 people
ANSWER:
Therefore, the answer is:
There are an average of 363 people per km^2 of land in India.
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Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
