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AleksAgata [21]
3 years ago
5

Solve for x. 3x/4 - X/12 =7/8 simplify your answer in fraction form ​

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

7/3

Step-by-step explanation:

or, 3x/4 - 7/8 = 7/8

or, 3x/4=7/8+7/8

or, 3x/4 = (7+7)/8

or, 3x/4 = 14/8

or, 3x = (14/8)*4

or, 3x=56/8

or, 3x= 7

or, x=7/3

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What is the first ordered pair and the second ordered pair?
Delvig [45]
When x=-5, y=(1/5)*(-5)-1=-2, so the first order pair is (-5,-2)
when y=-1, -1=(1/5)x-1, (1/5)x=0, x=0, so the second ordered pair is (0, -1)
7 0
3 years ago
Answer the question pls
masha68 [24]

Answer:

f=54

Step-by-step explanation:

ma is m times a 3x18= 54

6 0
3 years ago
Read 2 more answers
I need the answer please and can u answer my recent to.
ale4655 [162]

Answer:

30 hours.

Step-by-step explanation:

Richard can build 15 snowballs in 1 hour

But 2 snowballs melt every 15 minutes

In 1 hour, the number of snowballs that will have melted is:

\frac{60}{15} × 2 = 8

The number of snowballs that will have remained = 15 - 8 = 7

So 7 snowballs will have remained in 1 hour

For 210 snowballs to have remained, it will take:

\frac{210}{7} × 1 = 30 hours.

3 0
3 years ago
Tara has 4 4/5 feet of rope. Part A: How many 2/5 foot pieces can Tara cut from the 4 4/5 feet of rope? Show your work. Part B:
aleksley [76]

Answer:

Part A

12 pieces

Part B

Tara can cut Twelve 2/5 foot pieces can be cut from 4 4/5 feet of rope.

Step-by-step explanation:

Part A: How many 2/5 foot pieces can Tara cut from the 4 4/5 feet of rope?

This is calculated as:

4 4/5 feet of rope ÷ 2/5 foot pieces

= 24/5 ÷ 2/5

= 24/5 × 5/2

= 12

Part B: Using the information in Part A, interpret the meaning of the quotient in terms of the two fractions given

The quotient in Part A is 12

Therefore, this can be interpreted as:

Tara can cut Twelve 2/5 foot pieces can be cut from 4 4/5 feet of rope.

3 0
3 years ago
Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

7 0
3 years ago
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