Box one ratios
Box two 35:2= 70:4
If R is between Q and S then QR+RS=QS
given
QR=x+4
RS=3x-1
and QS=27
x+4+3x-1=27
combine like terms
4x+3=27
minus 3 both sides
4x=24
divide both sides by 4
x=6
sub back
QR=x+4
QR=6+4
QR=10
RS=3x-1
RS=3(6)-1
RS=18-1
RS=17
x=6
QR=10
RS=17
3 is 1/6 of the numbers on the cube so you do 642 X 1/6 and get 107 as the answer
Answer: x=1
Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*x+2*(5*x-3)-(7)=0
3x + 2 • (5x - 3)) - 7 = 0
Pull out like factors :
13x - 13 = 13 • (x - 1)
13 = 0
A a non-zero constant never equals zero.
Solve : x-1 = 0
Add 1 to both sides of the equation :
x = 1