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2 years ago

Evaluate 3^2 + (7 − 2) ⋅ 4 − 6 over 3

Mathematics

2 answers:

goldfiish [28.3K]2 years ago

6 0

Answer:

7.7

Step-by-step explanation:

we basically follow the BEDMAS rule

1st we workout the bracket (7-2)=5

2nd the exponent 3^2=9

3rd the multiplication (7-2) . 4 = 5 . 4 = 20

4th addition 9+20=29

5th step is subtraction 29-6=23

the final step is dividing 23 by 3, which will become 7.7

Lemur [1.5K]2 years ago

6 0

Answer: 27

<u>Step-by-step explanation:</u>

Use PEMDAS

3² + (7 - 2) · 4 - 6/3

Parenthesis: ↓

3² + 5 · 4 - 6/3

Exponents: ↓

9 + 5 · 4 - 6/3

Multiplication & Division: ↓ ↓

9 + 20 - 2

Addition & Subtraction: ↓ ↓

29 - 2 = 27

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Y=x2+6x+2 in vertex form

ahrayia [7]

I hope this helps you

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3 years ago

A basketball team played six games. In those games, the team won by 7 points, lost by 7, won by 8, won by 9, lost by 4, and won

Gemiola [76]

Based on the difference in scores for the basketball team over the six games, the mean difference in scores was 3

<h3>How to find the mean difference in scores?</h3>

The basketball team had 6 games and in these games, their scores were listed as differences in game scores.

The mean of these differences in scores can be found by adding the differences where they won and subtracting the differences where they lost and then dividing by the number of games:

The mean difference in game scores is:

= (7 - 7 + 8 + 9 - 4 + 5) / 6

= 18 / 6

= 3

Find out more on the mean differences at brainly.com/question/11323789

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7 0

1 year ago

Which of the following is NOT a variation of a Pythagorean identity?

Ipatiy [6.2K]

The expression that is not a variation of the Pythagorean identity is the third option.

<h3>What is the Pythagorean identity?</h3>

The Pythagorean identity can be written as:

$sin^2(x) + cos^2(x) = 1$

For example, if we subtract cos^2(x) on both sides we get the second option:

$sin^2(x) = 1 - cos^2(x)$

Which is a variation.

Now, let's divide both sides by cos^2(x).

$sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)\\\\tan^2(x) + 1 = sec^2(x)\\\\tan^2(x) - sec^2(x) = -1$

Notice that the third expression in the options looks like this one, but the one on the right side is positive. The above expression is in did a variation of the Pythagorean identity, then the one written in the options (with the 1 instead of the -1) is incorrect, meaning that it is not a variation of the Pythagorean identity.

Concluding, the correct option is the third one.

If you want to learn more about the Pythagorean identity, you can read:

brainly.com/question/24287773

3 0

2 years ago

MATH Simplify the expression -6w + (-8) + 1 + (-7w)

Luba_88 [7]

Answer: -13w - 7

Step-by-step explanation:

-6w + (-8) + 1 + (-7w)

Combine the like terms

-8 + 1 = -7

-6w + (-7) + (-7w)

-6w + (-7w) = -13w

-13w + (-7)

However, because adding a negative number is the same as subtracting the number as a positive, you can just make it -13w - 7

3 0

2 years ago

There were 237 people who went to a theater. Of those people, 127 arrived early and 68 arrived on time. The rest of the people a

True [87]

42 arrived late

You add 127 and 68 to get 195 then you subtract 237 to get 47.

3 0

2 years ago