Answer=72%
25-7=18purple clips
18 x
____=____
25 100
cross multiply
25x=1800
divide both sides by 25
x=72%
Answer:
36.58% probability that one of the devices fail
Step-by-step explanation:
For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
A total of 15 devices will be used.
This means that ![n = 15](https://tex.z-dn.net/?f=n%20%3D%2015)
Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.
This means that ![p = 0.05](https://tex.z-dn.net/?f=p%20%3D%200.05)
What is the probability that one of the devices fail?
This is ![P(X = 1)](https://tex.z-dn.net/?f=P%28X%20%3D%201%29)
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B15%2C1%7D.%280.05%29%5E%7B1%7D.%280.95%29%5E%7B14%7D%20%3D%200.3658)
36.58% probability that one of the devices fail
Answer:
Day 2
Step-by-step explanation:
Every 20 days, one jar is full.
To find when it was 1/8 full, we multiply the 20 days by 1/8.
20 x 1/8 = 2
Day 2
Answer:
93
Step-by-step explanation:
78+9+(10-4)=
78+9+6=
93