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bagirrra123 [75]
3 years ago
11

Complete the factor 14x^5=2x^3•(?)

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

\huge14 {x}^{ 5 }  = 2 {x}^{3} . \boxed{7 {x}^{2} }

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PLEASE HELP ME WITH THIS ASAP
balu736 [363]

Answer:

4 rows

Step-by-step explanation:

First set:

unknown rows, 5 tiles each

meaning old total is divisible by 5

Second set:

3 additional rows, 3 tiles each

meaning that the new total is divisible by 3

so, our total number of tiles is divisible by 5, add 1 and it is divisible by 3 when added 1<em> </em>

<em>{another way I solved it : [and when it is divided by 3, it has 8 that fit into the original pattern; which is another way of knowing that each of the rows of 5 [each have 2 removed when turned into rows of 3] add up to having a remainder of 8 tiles; 8 / 2 = 4; so there were four rows in the original pattern contributing to the change--</em><em>there were four rows</em><em>] }</em>

x is divisible by 5, x + 1 is divisible by 3

essentially, we are looking for a number that ends in 5 or 0, and the next number [ending in 6 or 1] is divisible by 3

I know that 5 goes into 20, and that 21 is divisible by 3, so let's test it out:

4 (rows of 5) turns into 7 [4 + 3] rows of 3

because 21 can be split into 7 rows, this number of tiles is possible

so, in the original pattern, there must have been 4 rows

hope this helps!! {so sorry if this confuses you, please let me know if I should explain my reasoning further}

have a lovely day :)

8 0
3 years ago
Help pleaseeeee!!! &lt;3
creativ13 [48]

Answer:

The 3rd one.

Step-by-step explanation:

4 0
3 years ago
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Alex787 [66]
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7 0
3 years ago
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An inequality represents an infinite amount of numbers smaller than 8. Which inequality represents the situation?
Kipish [7]

Answer:

it is B i took the test

Step-by-step explanation:

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3 years ago
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A student is deriving the quadratic formula. Her first two steps are shown. Step 1: –c = ax2 + bx Step 2: -c = a[x^2+b/ax] Which
marta [7]

Given choices:

(1) division property of equality

(2) factoring the binomial

(3)completing the square

(4)subtraction property of equality

Answer : (2) factoring the binomial

Step 1: -c = ax^2 + bx

Step 2:-c = a[x^2+\frac{b}{a} x]

In step 2, 'a' is taken out from ax^2 + bx. when we take out 'a' we divide each term by 'a'. so it becomes a[x^2+\frac{b}{a} x]

'a' is factored out in step 2. we call it as factoring a binomial.



6 0
3 years ago
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