Answer:
74.0°
Step-by-step explanation:
In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree
Solution:
A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.
Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:
In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.
Using sine rule, we can find ∠K:
First, make an organized list of the factors for each number. The common factors are 1, 2, 4, 8, and 16, and the greatest of these is 16. So, the greatest common factor or GCF of 48 and 64 is 16.
The answer is 5/2. The equation is already in point slope form. If you recall, the equation for point slope form is y-y1 = m(x-x1) where y1 and x1 are points on the graph, and m is the slope. In the given equation, m is 5/2 so we know it is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.
Answer:
one thousandth is greater than 0.061
Step-by-step explanation:
5n≥25
and if you divide 5 on both sides, n≥5 (I don't know if you are supposed to solve or simply put it in the equation form).
Product refers to multiplication. so 5 and n are being multiplied in the equation.
However, instead of using an equal sign, the sign for "greater than or equal to" must be used. "At least" is a term equivalent to "greater than or equal to".
