I think
sqrt 7x^2 - 7*sqrt 49x
x sqrt7 - 7 (7) sqrtx
x sqrt7 - 49 sqrtx
Answer:
I think you need to multiply 12 and 7 and then cut that in half
Answer:
Step-by-step explanation:
Its like doing a long division with base 10 numbers:
1110 <----------- Quotient
101)1001010
101
1000
101
111
101
100
So the answer is 1110 remainder 100.
We can confirm this by converting to decimal numbers
1001010 = 74 and 101 = 5.
74 / 5 = 14 remainder 4.
Answer:
0.013
0.031
0.03
0.1
I hope my answer's correct.
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
