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tensa zangetsu [6.8K]
3 years ago
10

The scatter plot shows the relationship between the number of hours spent jogging and the number of minutes spent stretching, by

the students on a track team:
A scatter plot is shown titled fitness routine. The x-axis is labeled hours jogging and the y-axis is labeled minutes stretching. Data points are located at 0 and 1, 2 and 1, 2 and 2, 4 and 3, 4 and 5, 6 and 3, 7 and 5, 9 and 4. A line connects the points 0 comma 1 and 10 comma 6.
What is the y-intercept of the line of best fit and what does it represent? (4 points)


1 minute; the number of minutes students stretch when they do not jog

1 hour; the number of hours students jog when they do not stretch

4 hours; the number of hours students jog when they do not stretch

4 minutes; the number of minutes students stretch when they do not jog


4.
(06.04)

The line of best fit for a scatter plot is shown:

A scatter plot and line of best fit are shown. Data points are located at 0 and 1, 2 and 1, 2 and 3, 4 and 3, 4 and 5, 6 and 3, 7 and 5, 9 and 4. A line of best fit passes through the y-axis at 1 and through the point 4 and 3.
What is the equation of this line of best fit in slope-intercept form? (4 points)


y = 1x + one half

y = one halfx + 1

y = 1x − one half

y = negative one halfx + 1


5.
(06.04)

The graph shows the number of cakes sold at Karen's Cake Shoppe for each of their 7 weeks in business:

A scatter plot is shown with the title Karens Cake Shoppe. The x axis is labeled Weeks in Business, and the y axis is labeled cakes sold. The data points are located at 1 and 2, 2 and 4, 3 and 5, 4 and 4, 5 and 6, 6 and 5, and 7 and 8. A line of best fit passes through the y axis at 1 and through the point 10 and 10.
If her current pattern continues, how many cakes will Karen most likely sell in her 10th week of business? (4 points)


10, because approximately y = 9 over 10.x + 1

11, because approximately y = 9 over 10.x + 1

8, because approximately y = 1x − 1

12, because approximately y = 1x + 2
Mathematics
1 answer:
kati45 [8]3 years ago
6 0
The y-intercept of the first question is 1 and it represents the number of minutes they stretch when they don't jog.
#4) y=1/2x + 1
#5) 10 cakes, because y=9/10x+1

Explanation
For the first question:  The y-intercept is easily picked from the two points that define the line.  (0, 1) would have to be on the y-axis, because when we plot it, the x-coordinate is 0.  This means it is the y-intercept of the line.

#4) Finding the slope of the line, we use the formula 
m=(y₂-y₁)/(x₂-x₁) = (3-1)/(4-0) = 2/4 = 1/2

The y-intercept is at (0, 1), using the same justification as the first question.
This gives us the equation y = 1/2x + 1.

#5) First we find the equation of the line.  To do this, find the slope:
m=(y₂-y₁)/(x₂-x₁) = (10-1)/(10-0) = 9/10

The y-intercept is at (0, 1).  This makes our equation y=9/10x + 1.

Using 10 as x (x represents the number of weeks) we have
y=9/10(10) + 1
y=9/10(10/1) + 1
y=90/10 + 1
y=9+1 = 10
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The GCF of two numbers is 3 and the LCM is 180. If the one of the number is 45, what is the other number?
NeTakaya

Answer:

45

Step-by-step explanation:

45 = 3*3*5

180 = 2*2*3*3*5 <---- so the other number had to contain a factor of 2*2 or 4

also, let the other number has to be of the form 3k and it must contain a factor of 4, how about 12 ?

check: lcf of 12 and 45 is 3,

the lcm of 12 and 45 is ...

12 = 2*2*3

45 = 3*3*5

so we need: 2*2*3*3*5 = 180

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3 years ago
The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviat
aleksley [76]

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be   =   \text{N}

each entry in survey be  =  \text{x}_{i}

mean of survey is     =     \mu  =3.5 \text{hours}

standard deviation is  =   \sigma = 2 \text{hours}

if each entry in survey is increased by one hour then,

each new entry in survey  is =  \text{x}_{i}+1

the new mean is\mu_{new}  = \frac{\text{sum of all hours}}{total number of entries}

                                                \frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}+\frac{\text{N}\times1 }{N}

                                             \mu_{new} = \mu + 1=4.5 \text{hours}

now,

standard deviation is      \sigma_{new}= \sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}

                                   \text{x}_{inew}= \text{x}_{i}+1

                                   \mu_{new}=\mu+1        

putting values,

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}= \sigma

                                 \sigma_{new}        =2

new mean and standard deviation are 4.5 and 2 \text{hours}

                                               

5 0
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Answer:

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Step-by-step explanation:

we have

f(x)=x^{3}-5x^{2}+5x-1

using a graphing tool  

see the attached figure

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The local minimum is the point (2.72,-4.27)

The zeros of the function are (0.27,0), (1,0), (3.73,0)

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Answer:

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we know that

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see the attached figure to better understand tyhe problem

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In the right triangle ABD

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h^2=\frac{3}{4}b^2

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3 years ago
Which expression is equivalent n + n - 0.24n?​
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Answer:

Without seeing the expressions that you can choose from, I can't tell you which one is correct, but I can tell you that n + n - 0.24n is equal to 1.76n

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