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My name is Ann [436]
3 years ago
8

Outcome

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

The expected value of the random variable with the given probability distribution = 12 .52

Step-by-step explanation:

Given data

 x    :   0         1            5       10     1000

p(x)  :  0.33  0.32   0.24     0.10    0.01

<em>The expected value of the given random variable of given probability distribution</em>

<em>E(X)  =  ∑ x p ( X = x)</em>

E(X)  =  0 × 0.33 + 1 × 0.32 + 5 × 0.24 + 10× 0.10 + 1000×0.01

<em>E (X)  =  12.52</em>

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