Ask question

Ask question

All categories

3 years ago

7

For a company picnic, Brian ordered a box of fresh-baked gingerbread cookies and sugar cookies. The box included a total of 60 c

ookies, and 90% of them were gingerbread. How many gingerbread cookies did Brian get?

1 answer:

IceJOKER [234]3 years ago

7 0

Answer:

54

fifty four of the cookies in the box were gingerbread cookies and the other 6 were sugar cookies

You might be interested in

The area of Canada is approximately

Alika [10]

Answer:

5

Step-by-step explanation:

10,000,000÷2,000,000=5

(1x10^7)÷ (2x10^6) = 5

8 0

3 years ago

Consider the following equations:

Dmitry [639]

Answer:

The Answer is: (-2,1)

Step-by-step explanation:

8 0

3 years ago

What is the what's the value of 2 million

Marysya12 [62]

The value of 2 million is 2,000,000

7 0

2 years ago

Read 2 more answers

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Solve the equation for the indicated variable (for q)<br><img src="https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7Bq%7D%7B4%7D%20

Salsk061 [2.6K]

Answer:

q=4(p-r)

Step-by-step explanation:

p-r=q/4

4(p-r)=q

7 0

3 years ago

Read 2 more answers